High School

Scores on an English test are normally distributed with a mean of 37.6 and a standard deviation of 7.6. Find the score that separates the top 59% from the bottom 41%.

A. 35.9
B. 39.3
C. 42.1
D. 33.1

Answer :

The score that separates the top 59% from the bottom 41% is 39.3.

To solve this problem, we need to find the z-score that separates the top 59% from the bottom 41%, and then use the z-score formula to find the corresponding raw score.

The z-score for the top 59% is the z-score that corresponds to a cumulative area of 0.59 to the left of it. We can find this using a standard normal table or a calculator:

z = invNorm(0.59) = 0.24

The z-score for the bottom 41% is the z-score that corresponds to a cumulative area of 0.41 to the left of it:

z = invNorm(0.41) = -0.24

The score that separates these two z-scores can be found using the z-score formula:

z = (x - μ) / σ

where x is the raw score, μ is the mean, and σ is the standard deviation. Solving for x, we get:

x = z * σ + μ

Plugging in the values we found earlier, we get:

x = 0.24 * 7.6 + 37.6 = 39.3

Therefore, the score that separates the top 59% from the bottom 41% is 39.3.

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