Answer :
Final answer:
The nuclear equation for the beta decay of Cerium-141 involves the formation of Praseodymium-141 with the release of an electron, an electron antineutrino, and energy.
Explanation:
The nuclear equation for the beta decay of Cerium-141 is:
14158Ce → 14159Pr + e-1 + ν + Energy
In this equation, Cerium-141 (denoted as 14158Ce) undergoes beta decay to form Praseodymium-141 (denoted as 14159Pr). An electron (denoted as e-1) and an electron antineutrino (denoted as ν) are emitted during the decay process, along with the release of energy.
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