Answer :
We are given that
[tex]$$
x^3 = 729.
$$[/tex]
Since we know that
[tex]$$
9^3 = 729,
$$[/tex]
it follows that
[tex]$$
x = 9.
$$[/tex]
Next, we need to evaluate
[tex]$$
x^2 + \sqrt{x}.
$$[/tex]
First, calculate [tex]$x^2$[/tex]:
[tex]$$
x^2 = 9^2 = 81.
$$[/tex]
Then, calculate the square root of [tex]$x$[/tex]:
[tex]$$
\sqrt{x} = \sqrt{9} = 3.
$$[/tex]
Now, add these two results:
[tex]$$
x^2 + \sqrt{x} = 81 + 3 = 84.
$$[/tex]
Thus, the final answer is [tex]$\boxed{84}$[/tex].
[tex]$$
x^3 = 729.
$$[/tex]
Since we know that
[tex]$$
9^3 = 729,
$$[/tex]
it follows that
[tex]$$
x = 9.
$$[/tex]
Next, we need to evaluate
[tex]$$
x^2 + \sqrt{x}.
$$[/tex]
First, calculate [tex]$x^2$[/tex]:
[tex]$$
x^2 = 9^2 = 81.
$$[/tex]
Then, calculate the square root of [tex]$x$[/tex]:
[tex]$$
\sqrt{x} = \sqrt{9} = 3.
$$[/tex]
Now, add these two results:
[tex]$$
x^2 + \sqrt{x} = 81 + 3 = 84.
$$[/tex]
Thus, the final answer is [tex]$\boxed{84}$[/tex].
