Answer :
The values chosen will depend on the specific requirements and constraints of the application. To design a low-pass filter using one resistor and one capacitor.
We can use the formula for the cutoff frequency of a first-order low-pass filter:
f_c = 1 / (2 * π * R * C)
where f_c is the cutoff frequency, R is the resistance, and C is the capacitance.
In this case, we want the cutoff frequency to be 159 Hz and the output voltage to be 4.24 volts when 6 volts at 159 Hz are applied at the input.
We can rearrange the formula to solve for either R or C:
R = 1 / (2 * π * f_c * C)
or
C = 1 / (2 * π * f_c * R)
Let's assume we know the value of either R or C, and solve for the other.
For example, if we choose a value of 1 kΩ for the resistance (R), we can calculate the value of the capacitance (C) using the rearranged formula:
C = 1 / (2 * π * f_c * R)
C = 1 / (2 * π * 159 Hz * 1000 Ω)
[tex]C ≈ 1.006 x 10^(-6) F[/tex]
To design a low-pass filter with a 1 kΩ resistor and a capacitance of approximately 1.006 µF, it should produce a 4.24-volt output at 159 Hz when 6 volts at 159 Hz are applied at the input.
To know about resistance visit:
https://brainly.com/question/32417106
#SPJ11
