Answer :
To find the acceleration, we start with Newton's second law, which states
[tex]$$
F = m \times a.
$$[/tex]
Here, [tex]$F$[/tex] is the force, [tex]$m$[/tex] is the mass, and [tex]$a$[/tex] is the acceleration. We can rearrange this equation to solve for acceleration:
[tex]$$
a = \frac{F}{m}.
$$[/tex]
Given the force [tex]$F = 156 \, \text{N}$[/tex] and the mass [tex]$m = 220 \, \text{kg}$[/tex], we substitute these values into the formula:
[tex]$$
a = \frac{156 \, \text{N}}{220 \, \text{kg}} \approx 0.70909 \, \text{m/s}^2.
$$[/tex]
Rounded to one decimal place, the acceleration is approximately [tex]$0.7 \, \text{m/s}^2$[/tex].
Thus, the correct answer is option A: [tex]$0.7 \, \text{m/s}^2$[/tex].
[tex]$$
F = m \times a.
$$[/tex]
Here, [tex]$F$[/tex] is the force, [tex]$m$[/tex] is the mass, and [tex]$a$[/tex] is the acceleration. We can rearrange this equation to solve for acceleration:
[tex]$$
a = \frac{F}{m}.
$$[/tex]
Given the force [tex]$F = 156 \, \text{N}$[/tex] and the mass [tex]$m = 220 \, \text{kg}$[/tex], we substitute these values into the formula:
[tex]$$
a = \frac{156 \, \text{N}}{220 \, \text{kg}} \approx 0.70909 \, \text{m/s}^2.
$$[/tex]
Rounded to one decimal place, the acceleration is approximately [tex]$0.7 \, \text{m/s}^2$[/tex].
Thus, the correct answer is option A: [tex]$0.7 \, \text{m/s}^2$[/tex].
