College

Find the requested function value for the given function. Round the answer to the nearest tenth when necessary.

If [tex]f(x)=\sqrt{2x-9}[/tex], find the value of [tex]f(29)[/tex].

A. 7
B. 58
C. 7.6
D. 49

Answer :

To find the value of [tex]\( f(29) \)[/tex] for the function [tex]\( f(x) = \sqrt{2x - 9} \)[/tex], follow these steps:

1. Substitute 29 for [tex]\( x \)[/tex]:
The function given is [tex]\( f(x) = \sqrt{2x - 9} \)[/tex]. So, we plug in 29 for [tex]\( x \)[/tex] to find [tex]\( f(29) \)[/tex].

[tex]\[
f(29) = \sqrt{2 \times 29 - 9}
\][/tex]

2. Calculate inside the square root:
First, multiply 2 by 29:

[tex]\[
2 \times 29 = 58
\][/tex]

Then, subtract 9 from 58:

[tex]\[
58 - 9 = 49
\][/tex]

3. Find the square root:
Now, calculate the square root of 49:

[tex]\[
\sqrt{49} = 7
\][/tex]

4. Round the result:
Since the result is already an integer, rounding [tex]\( 7 \)[/tex] to the nearest tenth yields [tex]\( 7.0 \)[/tex].

Therefore, the value of [tex]\( f(29) \)[/tex] is [tex]\( 7.0 \)[/tex].