Answer :
the power required to raise a load of 1260 kg from the lowest level to the top floor is approximately 207926.04 Watts (W).
To calculate the power required to raise a load in an elevator, we can use the formula:
P = F * v
where P is the power, F is the force applied, and v is the velocity.
Given:
Velocity, v = 16.83 m/s
Height, h = 382.2 m
Mass of the load, m = 1260 kg
To calculate the force, we need to consider the weight of the load:
Weight, W = m * g
where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.
Weight, W = (1260 kg) * (9.8 m/s^2) = 12348 N
The force applied is equal to the weight, since we are raising the load vertically against gravity.
Force, F = 12348 N
Now we can calculate the power:
P = F * v = (12348 N) * (16.83 m/s) = 207926.04 W
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