Answer :
To produce 298 g of potassium chloride (KCl) in the reaction 2K + Cl2 → 2KCl, approximately 156.4 grams of potassium (K) is required.
To determine the amount of potassium (K) required to produce 298 g of potassium chloride (KCl), we need to use the stoichiometry of the balanced chemical equation.
The balanced equation is: 2K + Cl2 → 2KCl
From the equation, we can see that for every 2 moles of potassium (K), 2 moles of potassium chloride (KCl) are produced. Therefore, the mole ratio between K and KCl is 2:2 or 1:1.
To calculate the amount of potassium required, we can use the following steps:
1. Determine the molar mass of KCl:
Molar mass of KCl = (39.1 g/mol) + (35.4 g/mol) = 74.5 g/mol
2. Calculate the number of moles of KCl:
Moles of KCl = mass of KCl / molar mass of KCl
Moles of KCl = 298 g / 74.5 g/mol = 4 moles
3. Since the mole ratio between K and KCl is 1:1, the number of moles of potassium required is also 4 moles.
4. Calculate the mass of potassium required:
Mass of K = moles of K × molar mass of K
Mass of K = 4 moles × 39.1 g/mol = 156.4 g
Therefore, to produce 298 g of KCl, approximately 156.4 grams of potassium (K) is required.
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