Answer :
To solve this problem, we will use the properties of the sampling distribution of the sample mean. Here are the steps:
1. Identify the Known Values:
- Population mean ([tex]\( \mu \)[/tex]) = 50
- Population standard deviation ([tex]\( \sigma \)[/tex]) = 18
- Sample size ([tex]\( n \)[/tex]) = 64
2. Calculate the Standard Error of the Mean (SEM):
The standard error is calculated using the formula:
[tex]\[
\text{Standard Error} = \frac{\sigma}{\sqrt{n}}
\][/tex]
Substituting the given values:
[tex]\[
\text{Standard Error} = \frac{18}{\sqrt{64}} = \frac{18}{8} = 2.25
\][/tex]
3. Find the Probability for Each Case:
We will use the Z-score formula to convert the sample mean to a Z-score, and then find the probabilities using the standard normal distribution table.
a. Probability that the sample mean is greater than 54 ([tex]\( P(\bar{x} > 54) \)[/tex]):
- Calculate the Z-score for 54:
[tex]\[
z = \frac{54 - 50}{2.25} \approx 1.78
\][/tex]
- Find the probability using the Z-table or standard normal distribution:
[tex]\[
P(\bar{x} > 54) \approx 0.0377
\][/tex]
b. Probability that the sample mean is less than 54 ([tex]\( P(\bar{x} < 54) \)[/tex]):
- This is simply:
[tex]\[
P(\bar{x} < 54) = 1 - P(\bar{x} > 54) \approx 0.9623
\][/tex]
c. Probability that the sample mean is less than 49 ([tex]\( P(\bar{x} < 49) \)[/tex]):
- Calculate the Z-score for 49:
[tex]\[
z = \frac{49 - 50}{2.25} \approx -0.44
\][/tex]
- Find the probability:
[tex]\[
P(\bar{x} < 49) \approx 0.3284
\][/tex]
d. Probability that the sample mean is between 48.5 and 53.5:
- Calculate the Z-score for 48.5 and 53.5:
[tex]\[
z_1 = \frac{48.5 - 50}{2.25} \approx -0.67
\][/tex]
[tex]\[
z_2 = \frac{53.5 - 50}{2.25} \approx 1.56
\][/tex]
- Find the probability:
[tex]\[
P(48.5 \leq \bar{x} \leq 53.5) \approx 0.6876
\][/tex]
e. Probability that the sample mean is between 50.1 and 51.7:
- Calculate the Z-score for 50.1 and 51.7:
[tex]\[
z_1 = \frac{50.1 - 50}{2.25} \approx 0.04
\][/tex]
[tex]\[
z_2 = \frac{51.7 - 50}{2.25} \approx 0.76
\][/tex]
- Find the probability:
[tex]\[
P(50.1 \leq \bar{x} \leq 51.7) \approx 0.2573
\][/tex]
These results give the probabilities for each scenario regarding the sample mean.
1. Identify the Known Values:
- Population mean ([tex]\( \mu \)[/tex]) = 50
- Population standard deviation ([tex]\( \sigma \)[/tex]) = 18
- Sample size ([tex]\( n \)[/tex]) = 64
2. Calculate the Standard Error of the Mean (SEM):
The standard error is calculated using the formula:
[tex]\[
\text{Standard Error} = \frac{\sigma}{\sqrt{n}}
\][/tex]
Substituting the given values:
[tex]\[
\text{Standard Error} = \frac{18}{\sqrt{64}} = \frac{18}{8} = 2.25
\][/tex]
3. Find the Probability for Each Case:
We will use the Z-score formula to convert the sample mean to a Z-score, and then find the probabilities using the standard normal distribution table.
a. Probability that the sample mean is greater than 54 ([tex]\( P(\bar{x} > 54) \)[/tex]):
- Calculate the Z-score for 54:
[tex]\[
z = \frac{54 - 50}{2.25} \approx 1.78
\][/tex]
- Find the probability using the Z-table or standard normal distribution:
[tex]\[
P(\bar{x} > 54) \approx 0.0377
\][/tex]
b. Probability that the sample mean is less than 54 ([tex]\( P(\bar{x} < 54) \)[/tex]):
- This is simply:
[tex]\[
P(\bar{x} < 54) = 1 - P(\bar{x} > 54) \approx 0.9623
\][/tex]
c. Probability that the sample mean is less than 49 ([tex]\( P(\bar{x} < 49) \)[/tex]):
- Calculate the Z-score for 49:
[tex]\[
z = \frac{49 - 50}{2.25} \approx -0.44
\][/tex]
- Find the probability:
[tex]\[
P(\bar{x} < 49) \approx 0.3284
\][/tex]
d. Probability that the sample mean is between 48.5 and 53.5:
- Calculate the Z-score for 48.5 and 53.5:
[tex]\[
z_1 = \frac{48.5 - 50}{2.25} \approx -0.67
\][/tex]
[tex]\[
z_2 = \frac{53.5 - 50}{2.25} \approx 1.56
\][/tex]
- Find the probability:
[tex]\[
P(48.5 \leq \bar{x} \leq 53.5) \approx 0.6876
\][/tex]
e. Probability that the sample mean is between 50.1 and 51.7:
- Calculate the Z-score for 50.1 and 51.7:
[tex]\[
z_1 = \frac{50.1 - 50}{2.25} \approx 0.04
\][/tex]
[tex]\[
z_2 = \frac{51.7 - 50}{2.25} \approx 0.76
\][/tex]
- Find the probability:
[tex]\[
P(50.1 \leq \bar{x} \leq 51.7) \approx 0.2573
\][/tex]
These results give the probabilities for each scenario regarding the sample mean.