Answer :
To solve the division problem [tex]\(1564 \div 234\)[/tex], we want to find both the quotient and the remainder. Let's go through the steps:
1. Divide: Begin by dividing [tex]\(1564\)[/tex] by [tex]\(234\)[/tex]. This gives us the quotient, which is the number of full times [tex]\(234\)[/tex] fits into [tex]\(1564\)[/tex].
2. Calculate Quotient: When you divide [tex]\(1564\)[/tex] by [tex]\(234\)[/tex], the quotient is [tex]\(6\)[/tex]. This means [tex]\(234\)[/tex] can fit into [tex]\(1564\)[/tex] exactly [tex]\(6\)[/tex] times without exceeding it.
3. Calculate Remainder: Multiply the quotient [tex]\(6\)[/tex] by the divisor [tex]\(234\)[/tex], and you get [tex]\(6 \times 234 = 1404\)[/tex]. Subtract this product from the original dividend: [tex]\(1564 - 1404 = 160\)[/tex].
So, the quotient is [tex]\(6\)[/tex] and the remainder is [tex]\(160\)[/tex]. Therefore, the division [tex]\(1564 \div 234\)[/tex] results in:
[tex]\[6 \, \text{remainder} \, 160\][/tex]
From the options given, the correct answer is:
A. [tex]\(6 \, \text{remainder} \, 160\)[/tex]
1. Divide: Begin by dividing [tex]\(1564\)[/tex] by [tex]\(234\)[/tex]. This gives us the quotient, which is the number of full times [tex]\(234\)[/tex] fits into [tex]\(1564\)[/tex].
2. Calculate Quotient: When you divide [tex]\(1564\)[/tex] by [tex]\(234\)[/tex], the quotient is [tex]\(6\)[/tex]. This means [tex]\(234\)[/tex] can fit into [tex]\(1564\)[/tex] exactly [tex]\(6\)[/tex] times without exceeding it.
3. Calculate Remainder: Multiply the quotient [tex]\(6\)[/tex] by the divisor [tex]\(234\)[/tex], and you get [tex]\(6 \times 234 = 1404\)[/tex]. Subtract this product from the original dividend: [tex]\(1564 - 1404 = 160\)[/tex].
So, the quotient is [tex]\(6\)[/tex] and the remainder is [tex]\(160\)[/tex]. Therefore, the division [tex]\(1564 \div 234\)[/tex] results in:
[tex]\[6 \, \text{remainder} \, 160\][/tex]
From the options given, the correct answer is:
A. [tex]\(6 \, \text{remainder} \, 160\)[/tex]
