High School

Water from a fire hose is directed horizontally against a wall at a rate of 55.1 kg/s and a speed of 39.1 m/s. Calculate the magnitude of the force exerted on the wall (in N), assuming the water's horizontal momentum is reduced to zero.

Answer :

The magnitude of the force exerted on the wall by the water from the fire hose is 2150.41 Newtons.

To calculate the magnitude of the force exerted on the wall is by using the equation for force:

force = rate of change of momentum

In this case, the rate of change of momentum is equal to the mass flow rate multiplied by the change in velocity. Since the water's horizontal momentum is reduced to zero, the change in velocity is equal to the initial velocity of the water.

So we have:

force = rate of change of momentum = mass flow rate * change in velocity

Plugging in the given values:

force = 55.1 kg/s * 39.1 m/s

Calculating this expression:

force = 2150.41 N

Therefore, the magnitude of the force exerted on the wall by the water from the fire hose is approximately 2150.41 Newtons.

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