Answer :
Sure, let's break down the problem step-by-step.
We are given the atomic mass of potassium, which is 39.1 grams per mole. Additionally, it is important to know Avogadro's number, which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms per mole. This number tells us how many atoms are in one mole of any substance.
The question asks us for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium.
1. Understanding the Problem:
- Atomic mass of potassium = 39.1 grams per mole
- Number of potassium atoms provided = [tex]\(6.02 \times 10^{23}\)[/tex] atoms
2. Connection Between Moles and Number of Atoms:
- By definition, 1 mole of potassium (or any element) contains [tex]\(6.02 \times 10^{23}\)[/tex] atoms.
3. Mass Calculation:
- Since [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is exactly 1 mole of potassium, we can directly use the given atomic mass to find the mass.
- Thus, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is simply the atomic mass of 1 mole of potassium.
4. Conclusion:
- Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.
So, the correct answer is:
B. [tex]\(39.1 \, \text{g}\)[/tex]
We are given the atomic mass of potassium, which is 39.1 grams per mole. Additionally, it is important to know Avogadro's number, which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms per mole. This number tells us how many atoms are in one mole of any substance.
The question asks us for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium.
1. Understanding the Problem:
- Atomic mass of potassium = 39.1 grams per mole
- Number of potassium atoms provided = [tex]\(6.02 \times 10^{23}\)[/tex] atoms
2. Connection Between Moles and Number of Atoms:
- By definition, 1 mole of potassium (or any element) contains [tex]\(6.02 \times 10^{23}\)[/tex] atoms.
3. Mass Calculation:
- Since [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is exactly 1 mole of potassium, we can directly use the given atomic mass to find the mass.
- Thus, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is simply the atomic mass of 1 mole of potassium.
4. Conclusion:
- Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.
So, the correct answer is:
B. [tex]\(39.1 \, \text{g}\)[/tex]
