Answer :
Final answer:
The probability that a randomly selected adult has a score greater than 139.1 in a normally distributed population, with mean of 97.4 and a standard deviation of 22 is 0.0285. So the answer is non all above the given option.
Explanation:
The problem asks us to find the probability that a randomly selected adult has a score greater than 139.1 in a normally distributed population of adults with a mean of 97.4 and a standard deviation of 22. To determine this probability, we need to calculate the z-score for the given score and use the z-table to find the corresponding probability. The formula to calculate the z-score is:
z = (x - mean) / standard deviation
In this case, x = 139.1, mean = 97.4, and standard deviation = 22.
Substituting these values into the formula, we get:
z = (139.1 - 97.4) / 22 = 1.9064
Using the z-table, we can find that the probability corresponding to a z-score of 1.9064 is approximately 0.9715.
However, we are interested in the probability of having a score greater than 139.1, so we subtract this probability from 1:
Probability = 1 - 0.9715 = 0.0285
Therefore, the correct answer is 0.0285, so the answer is non all above the given option.
Learn more about Probability here:
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