High School

Convert the following code into LEGv8. Assume g and h are in registers X19 and X20, respectively:

```c
if (g < h)
g = g + h;
else
h = h * 2;
```

Answer :

Final answer:

The pseudo-code if (g < h) g=g; else h = h * 2 can be translated into LEgV8 assembly language instructions as follows: Compare x19 and x20, branch to 'Else' if g is not less than h, move x19 to x20 if g is less, branch to 'EndIf', and perform a logical shift left on x20 if g is not less than h.

Explanation:

The presented pseudo-code can be translated into LEgV8 assembly instructions as follows:

  • CMP x19, x20: Compares the contents of register x19(g) and x20(h).
  • B.GE Else: Branch to the instruction labelled 'Else' if g is not less than h.
  • MOV x20, x19: Move the value of x19 to x20 if g is less than h.
  • B EndIf: Branch to the instruction labelled 'EndIf'.
  • Else: LSL x20, x20, #1: Logical Shift Left operation which effectively multiplies h by 2. This executes if g is not less than h.
  • EndIf: This is where the common part of the program continues.

Learn more about LEgV8 Assembly Programming here:

https://brainly.com/question/36745644

#SPJ11

Other Questions