Answer :
Final answer:
The pressure of 1 mole of an ideal gas maintained at 300K and 250cm³ is approximately 98.52 atm.
Explanation:
To calculate the pressure of an ideal gas, we can use the ideal gas law equation: PV = nRT.
Given:
- Number of moles (n) = 1 mole
- Temperature (T) = 300K
- Volume (V) = 250cm³
Substituting these values into the equation, we get:
P * 250cm³ = 1 mole * R * 300K
Since we are looking for the pressure (P), we can rearrange the equation:
P = (1 mole * R * 300K) / 250cm³
Now, we can calculate the pressure using the given values:
P = (1 * 0.0821 * 300) / 0.25
P = 98.52 atm
Therefore, the pressure of 1 mole of an ideal gas maintained at 300K and 250cm³ is approximately 98.52 atm.
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