Answer :
Final answer:
To calculate the Ksp for hydroxide, we need to know the equation for the dissolution of Sn(OH)₂. The molar solubility of Sn(OH)₂ is (1.69 x 10⁻⁷ g/L) / (150.69 g/mol). The Ksp for hydroxide is approximately 1.35 x 10⁻²⁷. Therefore, the correct answer is option A).
Explanation:
In order to calculate the Ksp for hydroxide, we need to know the equation for the dissolution of Sn(OH)₂. The equation is: Sn(OH)₂(s) → Sn²⁺(aq) + 2OH⁻(aq). Since the solubility of Sn(OH)₂ is given in grams per liter, we need to convert it to molar solubility. The molar mass of Sn(OH)₂ is 150.69 g/mol, so the molar solubility is (1.69 x 10⁻⁷ g/L) / (150.69 g/mol).
To calculate the Ksp, we use the equation Ksp = [Sn²⁺][OH⁻]². Since the molar solubility of Sn(OH)₂ is equal to [Sn²⁺], and since there are 2 moles of OH⁻ for every mole of Sn(OH)₂, the concentration of OH⁻ is equal to twice the molar solubility of Sn(OH)₂. Therefore, we substitute the values into the equation: Ksp = (1.69 x 10⁻⁷ mol/L) x 2(1.69 x 10⁻⁷ mol/L)².
Simplifying the equation, we get Ksp ≈ 1.35 x 10⁻²⁷. Therefore, the correct answer is option A) 1.35 x 10⁻²⁷.
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