Answer :
Question: The probability that cars passing a speed camera are speeding is 0.25 If 752 cars pass the camera, how many of the cars would you expect to be speeding and what would be the variance?
To calculate the expected number of cars that would be speeding, we multiply the probability of a car speeding (0.25) by the total number of cars passing the camera (752):
Expected number of speeding cars = 0.25 * 752 = 188
Therefore, we would expect approximately 188 of the 752 cars to be speeding.
To calculate the variance, we use the formula:
Variance (V(X)) = n * p * (1 - p)
where n is the number of trials (cars passing the camera) and p is the probability of success (probability of a car speeding).
V(X) = 752 * 0.25 * (1 - 0.25) = 141
So, the variance would be 141.
Therefore, the correct answer is: E(X) = 188 and V(X) = 141.
Learn more about probability : https://brainly.com/question/13604758
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