Answer :
Final answer:
The heat energy required to raise the temperature of 20 kg of water from 10°C to 50°C is 3,347,200 joules, calculated using the specific heat capacity equation.
Explanation:
The heat energy required to raise the temperature of a substance can be calculated using the specific heat capacity formula: Q = mcΔT, where Q is the heat energy in joules, m is the mass in kilograms, c is the specific heat capacity in J/kg/°C, and ΔT is the change in temperature in degrees Celsius.
To calculate the heat energy required to raise the temperature of 20 kg of water (H2O) from 10 degrees Celsius to 50 degrees Celsius, we use the given specific heat capacity of water, which is 4,184 J/kg/°C:
Q = mcΔT
Q = (20 kg)(4,184 J/kg/°C)(50°C - 10°C)
Q = (20 kg)(4,184 J/kg/°C)(40°C)
Q = 3,347,200 J
Thus, the heat energy required is 3,347,200 joules.
