Answer :
The % composition of manganese (Mn) in KMnO4 is 34.8%.To calculate the % composition of manganese (Mn) in KMnO4, we need to determine the mass of Mn in one mole of KMnO4.
The molar mass of KMnO4 can be calculated as follows:
Molar mass of KMnO4 = (39.1 g/mol for K) + (1 x 55 g/mol for Mn) + (4 x 16 g/mol for O)
= 39.1 g/mol + 55 g/mol + 64 g/mol
= 158.1 g/mol
The molar mass of Mn in KMnO4 is 55 g/mol.
Now, to calculate the % composition of Mn in KMnO4, we divide the molar mass of Mn by the molar mass of KMnO4 and multiply by 100:
% composition of Mn = (55 g/mol / 158.1 g/mol) x 100
= 0.348 x 100
= 34.8%
Therefore, the % composition of manganese (Mn) in KMnO4 is 34.8%. Hence, option A (34.8%) is the correct answer.
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