Answer :
Let's solve the questions step-by-step:
Three less than a number.
Let the number be [tex]x[/tex]. Three less than this number means [tex]x - 3[/tex].
Four more than a number is eleven.
Again, let the number be [tex]x[/tex]. The equation for this statement is:
[tex]x + 4 = 11[/tex]
To find [tex]x[/tex], subtract 4 from both sides:
[tex]x = 11 - 4[/tex]
[tex]x = 7[/tex]The product of three and a number.
Let the number be [tex]x[/tex]. The product of three and this number is [tex]3x[/tex].
Eight more than double a number is nine.
Let the number be [tex]x[/tex]. The equation for this is:
[tex]2x + 8 = 9[/tex]
Subtract 8 from both sides:
[tex]2x = 9 - 8[/tex]
[tex]2x = 1[/tex]Divide both sides by 2 to find [tex]x[/tex]:
[tex]x = \frac{1}{2}[/tex]
A number divided by seven is two.
Let the number be [tex]x[/tex]. The equation is:
[tex]\frac{x}{7} = 2[/tex]
Multiply both sides by 7 to find [tex]x[/tex]:
[tex]x = 2 \times 7[/tex]
[tex]x = 14[/tex]The product of a number and six is eighteen.
Let the number be [tex]x[/tex]. The equation is:
[tex]6x = 18[/tex]
Divide both sides by 6 to find [tex]x[/tex]:
[tex]x = \frac{18}{6}[/tex]
[tex]x = 3[/tex]
These solutions help students understand how to translate word problems into algebraic expressions and equations, and then solve them to find the unknown values.