Answer :
Let's solve the division problem [tex]\(8,370 \div 62\)[/tex] and find both the quotient and the remainder.
1. Divide:
Begin by seeing how many times 62 can fit into 8370.
2. Calculate the Quotient:
- Determine how many times 62 goes into 837.
- 62 fits into 837 thirteen times because [tex]\(62 \times 13 = 806\)[/tex], which is the largest multiple of 62 below 837.
- Subtract 806 from 837 to get the remainder: [tex]\(837 - 806 = 31\)[/tex].
3. Bring Down the Next Digit:
- Bring down the next digit from 8370, which is 0, making it 310.
4. Continue the Division:
- Check how many times 62 fits into 310.
- 62 goes into 310 exactly five times because [tex]\(62 \times 5 = 310\)[/tex].
- Subtract 310 from 310 to get a remainder of 0.
5. Compile the Quotient and Remainder:
- The quotient is 135, and since the remainder is 0, it's a perfect division.
Therefore, the solution to [tex]\(8,370 \div 62\)[/tex] is a quotient of 135 and a remainder of 0.
1. Divide:
Begin by seeing how many times 62 can fit into 8370.
2. Calculate the Quotient:
- Determine how many times 62 goes into 837.
- 62 fits into 837 thirteen times because [tex]\(62 \times 13 = 806\)[/tex], which is the largest multiple of 62 below 837.
- Subtract 806 from 837 to get the remainder: [tex]\(837 - 806 = 31\)[/tex].
3. Bring Down the Next Digit:
- Bring down the next digit from 8370, which is 0, making it 310.
4. Continue the Division:
- Check how many times 62 fits into 310.
- 62 goes into 310 exactly five times because [tex]\(62 \times 5 = 310\)[/tex].
- Subtract 310 from 310 to get a remainder of 0.
5. Compile the Quotient and Remainder:
- The quotient is 135, and since the remainder is 0, it's a perfect division.
Therefore, the solution to [tex]\(8,370 \div 62\)[/tex] is a quotient of 135 and a remainder of 0.
