Answer :
The period of a pendulum is given by:
[tex]T=2\pi\sqrt{\frac{L}{g}}[/tex]where L is the length of the sting and g is the acceleration of gravity. In this case the length of the string is 0.250 m, plugging the values we have:
[tex]\begin{gathered} T=2\pi\sqrt{\frac{0.250}{9.8}} \\ T=1.00 \end{gathered}[/tex]Therefore, the period is 1.00 s
The period of oscillation of a pendulum can be calculated using a specific formula based on string length, amplitude, and mass, resulting in a period of approximately 1.00 seconds for the provided scenario.
The question posed relates to the period of oscillation of a pendulum. The period of oscillation of a pendulum is determined by the formula:
T = 2π√(L/g)
where T is the period, L is the length of the string, and g is the acceleration due to gravity. Given a string length of 0.250 m, amplitude of 0.100 m, and mass of 12.3 kg, g = 9.81 m/s². Plugging in the values, we calculate the period to be approximately 1.00 s.
