Answer :
To calculate the Shannon diversity index (H) for each community, we can use the formula: H = -∑(pi * ln(pi)), Where: pi represents the proportion (relative abundance) of each species in the community and ln represents the natural logarithm.
For Community 1:
- Number of individuals: 100
- Species A: 5 individuals (5/100 = 0.05)
- Species B: 5 individuals (5/100 = 0.05)
- Species C: 85 individuals (85/100 = 0.85)
- Species D: 5 individuals (5/100 = 0.05)
H = -[(0.05 * ln(0.05)) + (0.05 * ln(0.05)) + (0.85 * ln(0.85)) + (0.05 * ln(0.05))]
Calculating this equation gives us H ≈ 0.398
For Community 2:
- Number of individuals: 100
- Species A: 30 individuals (30/100 = 0.3)
- Species B: 40 individuals (40/100 = 0.4)
- Species C: 30 individuals (30/100 = 0.3)
H = -[(0.3 * ln(0.3)) + (0.4 * ln(0.4)) + (0.3 * ln(0.3))]
Calculating this equation gives us H ≈ 1.099
Comparing the Shannon diversity index (H) for each community, we can see that Community 2 has a higher diversity (H ≈ 1.099) compared to Community 1 (H ≈ 0.398). Therefore, Community 2 is more diverse than Community 1.
Learn more about Shannon diversity index here ;
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