Answer :
The mass of Na2O needed to release 105 kJ of heat energy is 97.4 g.
In the given reaction, the enthalpy change is -502 kJ when 1 mole of Na2O reacts with 2 moles of HI to produce 2 moles of NaI and 1 mole of H2O.
Using this information, we can calculate the enthalpy change for the given amount of heat energy as follows:
-502 kJ --> 1 mole Na2O
-105 kJ --> (105/502) mole Na2O [Using stoichiometry]
Therefore, the moles of Na2O required to release 105 kJ of heat energy is (105/502) mole. The molar mass of Na2O is 61.98 g/mol, so the mass of Na2O required can be calculated as:
Mass of Na2O = (105/502) mol x 61.98 g/mol = 97.4 g
Hence, the mass of Na2O needed to release 105 kJ of heat energy is 97.4 g.
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