College

Suppose you are using a Caterpillar 631E Scraper, with the specifications shown in Table 8.1 of the book and performance charts 8.8 and 8.9.

- Empty Vehicle Weight (EVW): 96,880 pounds
- Struck Capacity: 21 cubic yards
- Heaped Capacity: 31 cubic yards

Assume a 0.85-minute load time results in an average load of 96% of heaped capacity. The material to be hauled is sandy clay with a unit weight of 2,800 lb/bcy and a swell factor of 0.80.

What is the Gross Vehicle Weight (GVW)?

A. 170,209 lbs
B. 163,542 lbs
C. 173,264 lbs
D. 146,554 lbs

Answer :

Gross Vehicle weight(GVW) is 163542 lbs. So, The correct option b. 163542 lbs

Gross Vehicle weight(GVW) = empty vehicle weight(EVM) + average heaped load x material volume in LCY

empty vehicle weight = 96880 lb

average heaped load = 31 CY x 0.96 = 29.76 CY

material volume = 2800 x 0.8 = 2240 LCY

Gross Vehicle weight(GVW) = 96880 + 29.76 x 2240

Gross Vehicle weight(GVW) = 163542 lbs

Therefore, Gross Vehicle weight(GVW) is 163542 lbs.

option b. 163542 lbs is the answer

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