College

The sum of 4.6 and one-third of a number is at most 39.1. What are all the possible values of the number?

Artem wrote the inequality [tex]\frac{1}{3}n + 4.6 \leq 39.1[/tex], where [tex]n[/tex] equals the number, to help solve this problem.

Solve his inequality:

A. [tex]n \leq 131.1[/tex]

B. [tex]n \leq 112.7[/tex]

C. [tex]n \leq 103.5[/tex]

D. [tex]n \leq 11.5[/tex]

Answer :

To solve the inequality [tex]\( \frac{1}{3}n + 4.6 \leq 39.1 \)[/tex], follow these steps:

1. Isolate the term with [tex]\( n \)[/tex]:

Start by getting rid of the constant term (4.6) on the left side. To do this, subtract 4.6 from both sides of the inequality:

[tex]\[
\frac{1}{3}n + 4.6 - 4.6 \leq 39.1 - 4.6
\][/tex]

Simplifying both sides gives:

[tex]\[
\frac{1}{3}n \leq 34.5
\][/tex]

2. Solve for [tex]\( n \)[/tex]:

To isolate [tex]\( n \)[/tex], you need to get rid of the fraction [tex]\(\frac{1}{3}\)[/tex]. Multiply both sides by 3:

[tex]\[
3 \times \frac{1}{3}n \leq 3 \times 34.5
\][/tex]

This simplifies to:

[tex]\[
n \leq 103.5
\][/tex]

Therefore, the possible values of the number [tex]\( n \)[/tex] are such that [tex]\( n \leq 103.5 \)[/tex].

So the correct choice is [tex]\( n \leq 103.5 \)[/tex].