Suppose the scores of seven members of a women's golf team are [tex]$68, 62, 60, 64, 70, 66,$[/tex] and [tex]$72$[/tex]. Find the mean, median, and midrange.

a. Mean [tex]$=64$[/tex], median [tex]$=64$[/tex], midrange [tex]$=64$[/tex]
b. Mean [tex]$=65$[/tex], median [tex]$=64$[/tex], midrange [tex]$=66$[/tex]
c. Mean [tex]$=66$[/tex], median [tex]$=77$[/tex], midrange [tex]$=65$[/tex]
d. Mean [tex]$=66$[/tex], median [tex]$=66$[/tex], midrange [tex]$=66$[/tex]

Please select the best answer from the choices provided:

A
B
C
D

To solve the problem of finding the mean, median, and midrange for the golf team's scores, we'll review each step in detail:

1. Mean: The mean is the average score. To find it, add all the scores together and then divide by the number of scores.

[tex]\[
\text{Mean} = \frac{68 + 62 + 60 + 64 + 70 + 66 + 72}{7}
\][/tex]

When you add these numbers, the sum is 462. Dividing by 7 gives:

[tex]\[
\text{Mean} = \frac{462}{7} = 66
\][/tex]

2. Median: The median is the middle value in a list when the numbers are arranged in order. First, we arrange the scores in ascending order: 60, 62, 64, 66, 68, 70, 72. Since there are 7 scores (which is odd), the median is the fourth score:

[tex]\[
\text{Median} = 66
\][/tex]

3. Midrange: The midrange is the average of the highest and lowest scores. We find it by adding the smallest and largest numbers and then dividing by 2.

[tex]\[
\text{Midrange} = \frac{60 + 72}{2} = \frac{132}{2} = 66
\][/tex]

Based on these calculations, the mean is 66, the median is 66, and the midrange is 66. Therefore, the correct choice is:

d. Mean = 66, median = 66, midrange = 66