Answer :
The pressure at the bottom of the pool is approximately 98.1 kPa, which is option (a).
The pressure at the bottom of a pool that is 10 meters deep (at sea level) can be calculated using the formula:
P = ρgh
where P is the pressure, ρ is the density of the fluid (water), g is the acceleration due to gravity, and h is the depth of the fluid.
At sea level, the density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.81 m/s².
Plugging in the values, we get:
P = (1000 kg/m³) x (9.81 m/s²) x (10 m) = 98,100 Pa
Converting Pa to kPa, we get:
P = 98.1 kPa
Pressure in a fluid is defined as the force per unit area that the fluid exerts on any surface that it comes into contact with. The pressure at a point in a fluid depends on the depth of the fluid, the density of the fluid, and the acceleration due to gravity.
In the context of a pool, the water in the pool exerts a pressure on the bottom of the pool that depends on the depth of the pool. The deeper the pool, the higher the pressure at the bottom. This pressure can be calculated using the formula P = ρgh, where ρ is the density of the water, g is the acceleration due to gravity, and h is the depth of the pool.
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