Answer :
The three consecutive odd integers whose sum is 141 are 45, 47, and 49. We find these by setting up an equation where x represents the first integer and solving for x.
The question asks to find three consecutive odd integers whose sum is 141. To solve this, we let the first odd integer be x, the second be x + 2, and the third be x + 4. Since the sum of these three odd integers is 141, we can write the equation:
x + (x + 2) + (x + 4) = 141.
Solving the equation, we combine like terms to get 3x + 6 = 141. Subtracting 6 from both sides gives us 3x = 135. Dividing both sides by 3, we get x = 45. Therefore, the consecutive odd integers are 45, 47, and 49.
