Answer :
Final answer:
The change in momentum of the 7.3-kg bowling ball, when a force of 156 N is applied for 0.40 s, is 62.4 kg·m/s.
Explanation:
To calculate the change in momentum of the bowling ball, we can use the concept of impulse, which is equal to the change in momentum. The impulse experienced by an object is equal to the force applied to it times the time period over which the force is applied (Impulse = Force × Time).
In this problem, the force applied to the bowling ball is 156 N, and it is applied for a duration of 0.40 seconds. Therefore, to find the change in momentum, we multiply these two values:
Δp = F × t
Δp = 156 N × 0.40 s
Δp = 62.4 kg·m/s
This is the change in momentum experienced by the 7.3-kg bowling ball due to the applied force.
Answer:
[tex]62.4N\cdot s[/tex]
Explanation:
The change in momentum of the ball is equal to the impulse exerted on it, therefore:
[tex]\Delta p = I = F \Delta t[/tex]
where
[tex]\Delta p[/tex] is the change in momentum
F is the average force exerted on the ball
[tex]\Delta t[/tex] is the time during which the force is applied
In this problem,
F = 156 N
[tex]\Delta t = 0.40 s[/tex]
So, the change in momentum of the ball is
[tex]\Delta p =(156)(0.40)=62.4N\cdot s[/tex]
