Answer :
Final answer:
Using conservation of momentum, the velocity of the truck immediately after a collision, where it impacts a parked car and sets it in motion, is calculated to be 3.26 m/s.
Explanation:
The question involves the concept of conservation of momentum, which is a principle in physics stating that the total momentum of a closed system is constant if no external forces are acting on it. The original momentum of the truck before the collision can be calculated using the formula:
Momentum = mass × velocity
For the truck: Momentum = 3,141 kg × 7 m/s = 21987 kg·m/s
Since the parked car is initially at rest, it has no momentum before the collision. After the collision, the car is moving at 18 m/s, so its momentum is:
Momentum = 652 kg × 18 m/s = 11736 kg·m/s
According to the conservation of momentum, the total momentum before and after the collision must be the same, so we can set up the following equation:
21987 kg·m/s = 11736 kg·m/s + (3,141 kg × velocity of truck after collision)
Solving for the velocity of the truck after the collision, we get:
Velocity of truck after collision = (21987 kg·m/s - 11736 kg·m/s) / 3,141 kg
Velocity of truck after collision = 10251 kg·m/s / 3,141 kg = 3.26 m/s
Therefore, the velocity of the truck immediately after the collision is 3.26 m/s.
