High School

A number, [tex]n[/tex], is added to 15 less than 3 times itself. The result is 101. Which equation can be used to find the value of [tex]n[/tex]?

A. [tex]3n - 15 + n = 101[/tex]
B. [tex]3n + 15 + n = 101[/tex]
C. [tex]3n - 15 - n = 101[/tex]
D. [tex]3n + 15 - n = 101[/tex]

Answer :

To solve the problem, we need to set up an equation based on the information provided:

1. A number, [tex]\( n \)[/tex], is given.
2. You need to express "15 less than 3 times itself" in terms of [tex]\( n \)[/tex]. This can be written as [tex]\( 3n - 15 \)[/tex].
3. According to the problem, this expression ([tex]\( 3n - 15 \)[/tex]) is added to [tex]\( n \)[/tex].
4. The total result of this addition equals 101.

Therefore, the equation representing this situation is:

[tex]\[ n + (3n - 15) = 101 \][/tex]

Simplifying the equation:

- First, combine like terms:

[tex]\[ n + 3n - 15 = 101 \][/tex]
[tex]\[ 4n - 15 = 101 \][/tex]

The equation that can be used to find the value of [tex]\( n \)[/tex] is [tex]\( 3n - 15 + n = 101 \)[/tex], which matches the choice:

[tex]\[ 3n - 15 + n = 101 \][/tex]

This equation correctly represents the problem statement.