Answer :
To multiply the terms
[tex]$$4x, \quad -3x^8, \quad \text{and} \quad -7x^3,$$[/tex]
we work in two steps: first, multiply the coefficients (the numbers), then combine the powers of [tex]$x$[/tex].
1. Multiply the coefficients:
[tex]$$4 \times (-3) \times (-7).$$[/tex]
First, [tex]$4 \times (-3) = -12$[/tex]. Then, [tex]$-12 \times (-7) = 84.$[/tex]
2. Combine the exponents for [tex]$x$[/tex]:
When multiplying powers of the same base, we add the exponents:
[tex]$$x^1 \cdot x^8 \cdot x^3 = x^{1+8+3} = x^{12}.$$[/tex]
Thus, the product is:
[tex]$$84x^{12}.$$[/tex]
[tex]$$4x, \quad -3x^8, \quad \text{and} \quad -7x^3,$$[/tex]
we work in two steps: first, multiply the coefficients (the numbers), then combine the powers of [tex]$x$[/tex].
1. Multiply the coefficients:
[tex]$$4 \times (-3) \times (-7).$$[/tex]
First, [tex]$4 \times (-3) = -12$[/tex]. Then, [tex]$-12 \times (-7) = 84.$[/tex]
2. Combine the exponents for [tex]$x$[/tex]:
When multiplying powers of the same base, we add the exponents:
[tex]$$x^1 \cdot x^8 \cdot x^3 = x^{1+8+3} = x^{12}.$$[/tex]
Thus, the product is:
[tex]$$84x^{12}.$$[/tex]
