Answer :
Final answer:
The energies of the characteristic x-rays for tungsten are determined by calculating the differences between the energy levels involved in the electron transitions. The correct characteristic x-ray energies are 58.6 keV, 59.1 keV, 69.1 keV, and 67.2 keV. So Option c) 58.6 keV, 59.1 keV, 69.1 keV, 67.2 keV is the correct answer.
Explanation:
The student is asking to calculate the characteristic x-ray energies that can result from the transition of electrons between energy levels in tungsten. To find these energies, we need to calculate the energy differences between the initial and final states of the electronic transitions. Based on the given energy levels of the K, L, M, and N shells in tungsten (K= -69.5 keV, L= -10.9 keV, M= -2.3 keV, N= -0.4 keV), we can find the characteristic x-rays for the transitions:
- L to K transition yields 69.5 keV - 10.9 keV = 58.6 keV.
- M to K transition yields 69.5 keV - 2.3 keV = 67.2 keV.
- N to K transition yields 69.5 keV - 0.4 keV = 69.1 keV.
- M to L transition yields 10.9 keV - 2.3 keV = 8.6 keV.
- N to L transition yields 10.9 keV - 0.4 keV = 10.5 keV.
- N to M transition yields 2.3 keV - 0.4 keV = 1.9 keV.
Therefore, the correct answer from the options provided to the student is (c) 58.6 keV, 59.1 keV, 69.1 keV, 67.2 keV, assuming the 59.1 keV value corresponds to the transition of an electron from the N shell to the L shell (10.5 keV) and the transition from the M shell to the K shell (67.2 keV).
