Answer :
To find the volume of 10.1 grams of gold, we can use the formula for density, which is:
[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]
We can rearrange the formula to solve for volume:
[tex]\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \][/tex]
Given:
- Density of gold = [tex]\(19.3 \, \text{g/cm}^3\)[/tex]
- Mass of gold = [tex]\(10.1 \, \text{g}\)[/tex]
Now, substitute these values into the rearranged formula:
[tex]\[ \text{Volume} = \frac{10.1 \, \text{g}}{19.3 \, \text{g/cm}^3} \][/tex]
When you compute this, you find:
[tex]\[ \text{Volume} \approx 0.5233 \, \text{cm}^3 \][/tex]
Since 1 cm[tex]\(^3\)[/tex] is equivalent to 1 milliliter, the volume in milliliters is the same:
[tex]\[ \text{Volume} \approx 0.5233 \, \text{mL} \][/tex]
Thus, the volume of 10.1 grams of gold is approximately 0.5233 milliliters.
[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]
We can rearrange the formula to solve for volume:
[tex]\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \][/tex]
Given:
- Density of gold = [tex]\(19.3 \, \text{g/cm}^3\)[/tex]
- Mass of gold = [tex]\(10.1 \, \text{g}\)[/tex]
Now, substitute these values into the rearranged formula:
[tex]\[ \text{Volume} = \frac{10.1 \, \text{g}}{19.3 \, \text{g/cm}^3} \][/tex]
When you compute this, you find:
[tex]\[ \text{Volume} \approx 0.5233 \, \text{cm}^3 \][/tex]
Since 1 cm[tex]\(^3\)[/tex] is equivalent to 1 milliliter, the volume in milliliters is the same:
[tex]\[ \text{Volume} \approx 0.5233 \, \text{mL} \][/tex]
Thus, the volume of 10.1 grams of gold is approximately 0.5233 milliliters.
