High School

Calculate the number of moles of the indicated substance in each of the following samples:

a. 49.2 mg of sulfur trioxide ([tex]SO_3[/tex])

b. 7.44 x [tex]10^4[/tex] kg of lead(IV) oxide

c. 59.1 g of chloroform, [tex]CHCl_3[/tex]

d. 3.27 mg of trichloroethane, [tex]C_2H_3Cl_3[/tex]

e. 4.01 g of lithium hydroxide

Answer :

The number of moles of indicated substance in each sample is -

a) 6.14 x 10⁻⁴ mol

b) 3.1 x 10⁵ mol

c) 0.4 mol

d) 2.45 mol

e) 0.16 mol

To calculate number of moles of each substance in sample -

a) Sulfur trioxide

Given mass = 49.2 mg = 0.0492 g

Molar mass = 80.06 g/mol

Number of moles of sulfur trioxide = Given mass

Molar mass

= 0.0492g = 6.14 x 10⁻⁴mol

80.06 g/mol

b) Lead(iv) oxide

Given mass = 7.44 x 10⁴ kg = 7.44 x 10⁷ g

Molar mass = 239.2 g/mol

Number of moles of lead(iv)oxide = Given mass

Molar mass

= 7.44 x 10⁷g = 3.1 x 10⁵mol

239.2 g/mol

c) Chloroform (CHCl₃)

Given mass =59.1 g

Molar mass = 119.38 g/mol

Number of moles of chloroform = Given mass

Molar mass

= 59.1 g = 0.4 mol

119.38 g/mol

d) Trichloroethane (C₂H₃Cl₃)

Given mass = 3.27 mg = 0.00327 g

Molar mass = 133.4 g/mol

Number of moles of trichloroethane = Given mass

Molar mass

= 0.00327 g = 2.45 mol

133.4 g/mol

e) Lithium hydroxide

Given mass = 4.01 g

Molar mass = 23.95 g/mol

Number of moles of Lithium hydroxide = Given mass

Molar mass

= 4.01 g = 0.16 mol

23.95 g/mol

To learn more about moles,

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Final answer:

Number of moles of the elements boron is 2, manganese is 1, mercury is 0.50, bariumis 0.36, and lead is 0.19.

Explanation:

To calculate the number of moles of a substance, you can use the formula:

Number of moles = [tex]\frac{Mass of the sample (g)}{Molar mass of the substance (g/mol)}[/tex]

For each substance, you would first need to know its molar mass:

  • Boron (B) has a molar mass of about 10.81 g/mol.
  • Manganese (Mn) has a molar mass of about 54.94 g/mol.
  • Mercury (Hg) has a molar mass of about 200.59 g/mol.
  • Barium (Ba) has a molar mass of about 137.33 g/mol.
  • Lead (Pb) has a molar mass of about 207.2 g/mol.

Applying the formula:

  • a. Number of moles of Boron = 21.6 g / 10.81 g/mol = 2.00 moles
  • b. Number of moles of Manganese = 54.9 g / 54.94 g/mol ≈ 1.00 mole
  • c. Number of moles of Mercury = 100.3 g / 200.59 g/mol ≈ 0.50 moles
  • d. Number of moles of Barium = 50 g / 137.33 g/mol ≈ 0.36 moles
  • e. Number of moles of Lead = 40 g / 207.2 g/mol ≈ 0.19 moles