Answer :
Sure! Let's calculate how many grams are in 6.50 moles of [tex]\( \text{H}_2\text{SO}_4 \)[/tex].
Step 1: Identify the molar mass of [tex]\( \text{H}_2\text{SO}_4 \)[/tex].
The molar mass is the weight of one mole of a substance. For sulfuric acid ([tex]\( \text{H}_2\text{SO}_4 \)[/tex]), the molar mass is 98.1 grams per mole. This means one mole of [tex]\( \text{H}_2\text{SO}_4 \)[/tex] weighs 98.1 grams.
Step 2: Multiply the number of moles by the molar mass.
To find the grams of [tex]\( \text{H}_2\text{SO}_4 \)[/tex] in 6.50 moles, you simply multiply the number of moles by the molar mass:
[tex]\[
\text{Grams of } \text{H}_2\text{SO}_4 = \text{moles of } \text{H}_2\text{SO}_4 \times \text{molar mass of } \text{H}_2\text{SO}_4
\][/tex]
[tex]\[
\text{Grams of } \text{H}_2\text{SO}_4 = 6.50 \, \text{moles} \times 98.1 \, \text{grams/mole}
\][/tex]
[tex]\[
\text{Grams of } \text{H}_2\text{SO}_4 = 637.65 \, \text{grams}
\][/tex]
So, the amount of [tex]\( \text{H}_2\text{SO}_4 \)[/tex] in 6.50 moles is approximately 638 grams, which matches option (a).
Step 1: Identify the molar mass of [tex]\( \text{H}_2\text{SO}_4 \)[/tex].
The molar mass is the weight of one mole of a substance. For sulfuric acid ([tex]\( \text{H}_2\text{SO}_4 \)[/tex]), the molar mass is 98.1 grams per mole. This means one mole of [tex]\( \text{H}_2\text{SO}_4 \)[/tex] weighs 98.1 grams.
Step 2: Multiply the number of moles by the molar mass.
To find the grams of [tex]\( \text{H}_2\text{SO}_4 \)[/tex] in 6.50 moles, you simply multiply the number of moles by the molar mass:
[tex]\[
\text{Grams of } \text{H}_2\text{SO}_4 = \text{moles of } \text{H}_2\text{SO}_4 \times \text{molar mass of } \text{H}_2\text{SO}_4
\][/tex]
[tex]\[
\text{Grams of } \text{H}_2\text{SO}_4 = 6.50 \, \text{moles} \times 98.1 \, \text{grams/mole}
\][/tex]
[tex]\[
\text{Grams of } \text{H}_2\text{SO}_4 = 637.65 \, \text{grams}
\][/tex]
So, the amount of [tex]\( \text{H}_2\text{SO}_4 \)[/tex] in 6.50 moles is approximately 638 grams, which matches option (a).
