How many atoms of silicon would there be in a sample that contained [tex]4.66 \times 10^{30}[/tex] grams?

A. [tex]1.69 \times 10^{52}[/tex]
B. [tex]1.69 \times 10^{690}[/tex]
C. [tex]9.99 \times 10^{52}[/tex] (this rounds to [tex]1.0 \times 10^{53}[/tex])
D. [tex]9.99 \times 10^{690}[/tex] (this rounds to [tex]1.0 \times 10^{691}[/tex])

To find the number of atoms of silicon in the given sample, we need to use the mole concept and Avogadro's number. First, we need to find the number of moles of silicon in the sample by dividing the given mass by the molar mass of silicon. Then, we can use Avogadro's number to find the number of atoms of silicon.

Explanation:

To find the number of atoms of silicon in the given sample, we need to use the mole concept and Avogadro's number. First, we need to find the number of moles of silicon in the sample by dividing the given mass by the molar mass of silicon. The molar mass of silicon is approximately 28.09 grams/mol.

Number of moles of Si = (4.66 x 1030 grams) / (28.09 grams/mol) = 1.66 x 1029 moles

Next, we can use Avogadro's number, which is approximately 6.022 x 1023 atoms/mol, to find the number of atoms of silicon.

Number of atoms of Si = (1.66 x 1029 moles) x (6.022 x 1023 atoms/mol) = 9.99 x 1052 atoms

The number of atoms of Silicon in a sample that contained 4.66 x 10³⁰ grams is 9.99 x 10⁵².

To find the number of atoms of silicon in a sample that contained 4.66 x 10³⁰ grams, we first need to convert grams to moles, which we can do as follows:

Converting grams to moles using the molar mass of silicon (approximately 28.09 g/mol): 4.66 x 10³⁰ g ÷ 28.09 g/mol = 1.66 x 10²⁸ mol.

Using Avogadro's number (6.022 x 10²³ atoms/mol), we find the number of atoms: 1.66 x 10²⁸ mol x 6.022 x 10²³ atoms/mol = 9.99 x 10⁵² atoms of Silicon.

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