If [tex]f(3)=191.5[/tex] when [tex]r=0.03[/tex] for the function [tex]f(t)=P e^{rt}[/tex], then what is the approximate value of [tex]P[/tex]?

A. 175
B. 78
C. 210
D. 471

Answer :

Sure! Let's solve the problem step-by-step to find the approximate value of [tex]\( P \)[/tex].

We are given the function:
[tex]\[ f(t) = P e^{rt} \][/tex]

And we know:
- [tex]\( f(3) = 191.5 \)[/tex]
- [tex]\( r = 0.03 \)[/tex]

Our goal is to find the value of [tex]\( P \)[/tex].

1. Substitute the known values into the function:

Since [tex]\( f(3) = 191.5 \)[/tex], we substitute 3 for [tex]\( t \)[/tex] and 191.5 for [tex]\( f(3) \)[/tex]:

[tex]\[
191.5 = P e^{0.03 \times 3}
\][/tex]

2. Calculate the exponent:

The exponent in the equation is [tex]\( r \times 3 = 0.03 \times 3 = 0.09 \)[/tex].

3. Evaluate the exponential expression:

Calculate [tex]\( e^{0.09} \)[/tex]. This approximately equals 1.0941742837052104.

4. Solve for [tex]\( P \)[/tex]:

Rearrange the equation [tex]\( 191.5 = P \times 1.0941742837052104 \)[/tex] to solve for [tex]\( P \)[/tex]:

[tex]\[
P = \frac{191.5}{1.0941742837052104}
\][/tex]

This gives us [tex]\( P \approx 175.01782197944019 \)[/tex].

5. Determine the approximate value:

The closest answer choice to 175.01782 is 175.

So, the approximate value of [tex]\( P \)[/tex] is [tex]\( \boxed{175} \)[/tex].