Answer :
Final answer:
Given the total cost for 2 kilos of beef and 3 kilos of fish is less than Php 700, and a kilo of beef costs Php 250, the maximum cost of a kilo of fish to the nearest peso would be Php 67.
Explanation:
We have a constraint on the total cost of 2 kilos of beef and 3 kilos of fish which should be less than Php 700. We're also given that a kilo of beef costs Php 250. Thus, the total cost of beef for 2 kilograms would be:
= 2 * 250
= Php 500.
Subtracting this from the total constraint of Php 700 leaves us with Php 200 that can be spent on the fish. So, for three kilograms of fish, the maximum price per kilogram would be:
= Php 200/3
= Php 67.
As a result, the most expensive price of a kilogramme of fish in pesos would be Php 67.
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