Answer :
To determine how much work the eagle did on the fish, we use the formula for work:
[tex]\[ W = F \times d \][/tex]
where:
- [tex]\( W \)[/tex] is the work done,
- [tex]\( F \)[/tex] is the force applied,
- [tex]\( d \)[/tex] is the distance over which the force is applied.
In this scenario:
- The force [tex]\( F \)[/tex] applied by the eagle is 90 Newtons (N),
- The distance [tex]\( d \)[/tex] the eagle carries the fish upwards is 50 meters (m).
Now, let's calculate the work done:
1. Multiply the force by the distance:
[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]
2. Calculate the result:
[tex]\[ W = 4500 \, \text{Joules (J)} \][/tex]
Therefore, the eagle did 4500 Joules of work on the fish. The correct answer is 4500 J.
[tex]\[ W = F \times d \][/tex]
where:
- [tex]\( W \)[/tex] is the work done,
- [tex]\( F \)[/tex] is the force applied,
- [tex]\( d \)[/tex] is the distance over which the force is applied.
In this scenario:
- The force [tex]\( F \)[/tex] applied by the eagle is 90 Newtons (N),
- The distance [tex]\( d \)[/tex] the eagle carries the fish upwards is 50 meters (m).
Now, let's calculate the work done:
1. Multiply the force by the distance:
[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]
2. Calculate the result:
[tex]\[ W = 4500 \, \text{Joules (J)} \][/tex]
Therefore, the eagle did 4500 Joules of work on the fish. The correct answer is 4500 J.
