Answer :
To find out how much work the eagle did on the fish, we can use the formula for work, which is given by:
[tex]\[ W = F \times d \][/tex]
where:
- [tex]\( W \)[/tex] is the work done,
- [tex]\( F \)[/tex] is the force applied,
- [tex]\( d \)[/tex] is the distance over which the force is applied.
In this problem:
- The force ([tex]\( F \)[/tex]) applied by the eagle is 90 newtons,
- The distance ([tex]\( d \)[/tex]) the fish is carried is 50 meters.
Now we can substitute these values into the formula:
[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]
[tex]\[ W = 4500 \, \text{J} \][/tex]
Therefore, the work done by the eagle on the fish is 4500 joules. The correct answer is 4500 J.
[tex]\[ W = F \times d \][/tex]
where:
- [tex]\( W \)[/tex] is the work done,
- [tex]\( F \)[/tex] is the force applied,
- [tex]\( d \)[/tex] is the distance over which the force is applied.
In this problem:
- The force ([tex]\( F \)[/tex]) applied by the eagle is 90 newtons,
- The distance ([tex]\( d \)[/tex]) the fish is carried is 50 meters.
Now we can substitute these values into the formula:
[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]
[tex]\[ W = 4500 \, \text{J} \][/tex]
Therefore, the work done by the eagle on the fish is 4500 joules. The correct answer is 4500 J.
