Answer :
The period of oscillation of the system is 0.038 s.
The angular frequency of the system and the period of oscillation of a 0.313-kg mass attached to a spring with a force constant of 51.7 N/m are given as follows:
Angular frequency:
Angular frequency is defined as the ratio of the spring constant to the mass of an object and is denoted by the symbol ω. Mathematically, angular frequency, ω = k/mHere, the spring constant k = 51.7 N/m, and mass m = 0.313 kg. Substitute the values in the formula and solve for ω.ω = k/m = 51.7/0.313 = 165.1 rad/Therefore, the angular frequency of the system is 165.1 rad/s.Period of oscillation: The period of oscillation is defined as the time taken by the object to complete one full oscillation and is denoted by the symbol T. It is given by the formula: T = 2π/ωHere, ω = 165.1 rad/s.Substitute the values in the formula and solve for T.T = 2π/ω = 2π/165.1 = 0.038
Therefore, the period of oscillation of the system is 0.038 s.
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