Suppose the scores of seven members of a women's golf team are [tex]$68, 62, 60, 64, 70, 66,$[/tex] and [tex]$72$[/tex]. Find the mean, median, and midrange.

a. Mean [tex]$=64$[/tex], median [tex]$=64$[/tex], midrange [tex]$=64$[/tex]

b. Mean [tex]$=65$[/tex], median [tex]$=64$[/tex], midrange [tex]$=66$[/tex]

c. Mean [tex]$=66$[/tex], median [tex]$=77$[/tex], midrange [tex]$=65$[/tex]

d. Mean [tex]$=66$[/tex], median [tex]$=66$[/tex], midrange [tex]$=66$[/tex]

Please select the best answer from the choices provided:
A
B
C
D

To solve the problem of finding the mean, median, and midrange of the golf scores, let's go through the calculations step by step:

1. Mean:
- To find the mean (average), add up all the scores and then divide by the number of scores.
- The scores are: 68, 62, 60, 64, 70, 66, and 72.
- Add them up: [tex]$68 + 62 + 60 + 64 + 70 + 66 + 72 = 462$[/tex].
- There are 7 scores, so divide the total by 7: [tex]$\frac{462}{7} = 66$[/tex].
- Therefore, the mean is 66.

2. Median:
- The median is the middle number in a sorted list of numbers.
- First, arrange the scores in ascending order: 60, 62, 64, 66, 68, 70, 72.
- Since there are 7 scores, the middle score is the 4th one in the sorted list.
- The middle score is 66.
- Thus, the median is 66.

3. Midrange:
- The midrange is the average of the smallest and largest numbers in the set.
- The smallest score is 60 and the largest score is 72.
- Find the midrange by averaging them: [tex]$\frac{60 + 72}{2} = \frac{132}{2} = 66$[/tex].
- So, the midrange is 66.

Based on these calculations:

- Mean = 66
- Median = 66
- Midrange = 66

The correct answer is option D: Mean = 66, Median = 66, Midrange = 66.