Answer :
Final answer:
The number that leaves a remainder of 5 when divided by 8, and a remainder of 6 when divided by 7, is 53.
Explanation:
Based on the student's question, we are looking for a number that when divided by eight leaves a remainder of six, and when divided by seven leaves a remainder of five. This is a problem of congruence in the field of number theory.
Testing the available options, the answer turned out to be Option D, 53. When 53 is divided by 8, it leaves a remainder of 5. Furthermore, when it is divided by 7, it leaves a remainder of 6. Hence, it matched the properties mentioned in the question and is the correct answer.
To double check, let's do the math: 53 ÷ 8 = 6 Remainder 5 and 53 ÷ 7 = 7 Remainder 6. Therefore, 53 is indeed the number that meets the conditions stated.
Learn more about Number Theory here:
https://brainly.com/question/30414700
#SPJ11
