Suppose the scores of seven members of a women's golf team are [tex]68, 62, 60, 64, 70, 66, \text{and } 72[/tex]. Find the mean, median, and midrange.

a. Mean [tex]=64[/tex], median [tex]=64[/tex], midrange [tex]=64[/tex]

b. Mean [tex]=65[/tex], median [tex]=64[/tex], midrange [tex]=66[/tex]

c. Mean [tex]=66[/tex], median [tex]=77[/tex], midrange [tex]=65[/tex]

d. Mean [tex]=66[/tex], median [tex]=66[/tex], midrange [tex]=66[/tex]

Please select the best answer from the choices provided:

A

B

C

D

Sure! Let's find the mean, median, and midrange of the given scores: 68, 62, 60, 64, 70, 66, and 72.

### 1. Calculate the Mean:

The mean is the average of the scores. To find it, add up all the scores and then divide by the number of scores.

Scores: 68, 62, 60, 64, 70, 66, 72

- Sum of the scores:
[tex]\[
68 + 62 + 60 + 64 + 70 + 66 + 72 = 462
\][/tex]

- There are 7 scores.

- Mean:
[tex]\[
\frac{462}{7} = 66
\][/tex]

### 2. Find the Median:

The median is the middle score when all scores are arranged in ascending order. If there's an odd number of scores, it's simply the middle one. If there's an even number, it would be the average of the two middle scores.

- Arrange the scores in ascending order:
[tex]\[
60, 62, 64, 66, 68, 70, 72
\][/tex]

- Since there are 7 scores (which is odd), the 4th score is the median.

- Median:
[tex]\[
66
\][/tex]

### 3. Calculate the Midrange:

The midrange is the average of the lowest and highest scores.

- Lowest score:
[tex]\[
60
\][/tex]

- Highest score:
[tex]\[
72
\][/tex]

- Midrange:
[tex]\[
\frac{60 + 72}{2} = \frac{132}{2} = 66
\][/tex]

### Conclusion:

The results for the mean, median, and midrange are all 66. Therefore, the correct answer is:
- d. Mean = 66, median = 66, midrange = 66