Answer :
To express the sales information for the three stores in a [tex]\(3 \times 4\)[/tex] matrix, we need to organize the data based on the items each store sold. The matrix is structured such that each row represents a different store and each column represents a different product category: loaves of bread, quarts of milk, jars of peanut butter, and pounds of cold cuts.
Step-by-step solution:
1. Store I Sales Data:
- Loaves of bread: 80
- Quarts of milk: 40
- Jars of peanut butter: 12
- Pounds of cold cuts: 108
Therefore, the row for Store I is [tex]\( [80, 40, 12, 108] \)[/tex].
2. Store II Sales Data:
- Loaves of bread: 108
- Quarts of milk: 75
- Jars of peanut butter: 21
- Pounds of cold cuts: 147
Therefore, the row for Store II is [tex]\( [108, 75, 21, 147] \)[/tex].
3. Store III Sales Data:
- Loaves of bread: 50
- Quarts of milk: 30
- Jars of peanut butter: 0
- Pounds of cold cuts: 50
Therefore, the row for Store III is [tex]\( [50, 30, 0, 50] \)[/tex].
Putting these rows together, we form the [tex]\(3 \times 4\)[/tex] matrix as follows:
[tex]\[
\left[\begin{array}{rrrr}
80 & 40 & 12 & 108 \\
108 & 75 & 21 & 147 \\
50 & 30 & 0 & 50
\end{array}\right]
\][/tex]
Therefore, the correct answer is option C:
[tex]\[
\left[\begin{array}{rrrr}
80 & 40 & 12 & 108 \\
108 & 75 & 21 & 147 \\
50 & 30 & 0 & 50
\end{array}\right]
\][/tex]
Step-by-step solution:
1. Store I Sales Data:
- Loaves of bread: 80
- Quarts of milk: 40
- Jars of peanut butter: 12
- Pounds of cold cuts: 108
Therefore, the row for Store I is [tex]\( [80, 40, 12, 108] \)[/tex].
2. Store II Sales Data:
- Loaves of bread: 108
- Quarts of milk: 75
- Jars of peanut butter: 21
- Pounds of cold cuts: 147
Therefore, the row for Store II is [tex]\( [108, 75, 21, 147] \)[/tex].
3. Store III Sales Data:
- Loaves of bread: 50
- Quarts of milk: 30
- Jars of peanut butter: 0
- Pounds of cold cuts: 50
Therefore, the row for Store III is [tex]\( [50, 30, 0, 50] \)[/tex].
Putting these rows together, we form the [tex]\(3 \times 4\)[/tex] matrix as follows:
[tex]\[
\left[\begin{array}{rrrr}
80 & 40 & 12 & 108 \\
108 & 75 & 21 & 147 \\
50 & 30 & 0 & 50
\end{array}\right]
\][/tex]
Therefore, the correct answer is option C:
[tex]\[
\left[\begin{array}{rrrr}
80 & 40 & 12 & 108 \\
108 & 75 & 21 & 147 \\
50 & 30 & 0 & 50
\end{array}\right]
\][/tex]