Answer :
molar mass LiCl = 42.394 g/mol
number of moles solute:
n = mass of solute / molar mass
n = 39.4 / 42.394
n = 0.929 moles
Therefore:
Molarity = number of moles / volume ( L )
M = 0.929 / 1.59
M = 0.584 mol/L
number of moles solute:
n = mass of solute / molar mass
n = 39.4 / 42.394
n = 0.929 moles
Therefore:
Molarity = number of moles / volume ( L )
M = 0.929 / 1.59
M = 0.584 mol/L
Final answer:
The molarity of a solution made by dissolving 39.4 g of lithium chloride in 1.59 L of water is calculated to be 0.584 M, by first determining the number of moles of LiCl and then applying the formula for molarity.
Explanation:
To calculate the molarity of a solution made by dissolving 39.4 g of lithium chloride (LiCl) in enough water to make 1.59 L of solution, we need to follow these steps:
Calculate the number of moles of LiCl. The molar mass of LiCl is 42.39 g/mol. The number of moles is calculated as mass (g) ÷ molar mass (g/mol). So, for 39.4 g of LiCl, the calculation is 39.4 g ÷ 42.39 g/mol = 0.929 moles of LiCl.
Convert the volume of solution from liters to liters, which is already given as 1.59 L.
Calculate the molarity. Molarity is defined as moles of solute ÷ liters of solution. Therefore, the molarity is 0.929 moles ÷ 1.59 L = 0.584 M.
The molarity of the solution is 0.584 M.
