The quotient of [tex]\left(x^4+5x^3-3x-15\right)[/tex] and [tex]\left(x^3-3\right)[/tex] is a polynomial. What is the quotient?

A. [tex]x^7+5x^6-6x^4-30x^3+9x+45[/tex]

B. [tex]x-5[/tex]

C. [tex]x+5[/tex]

D. [tex]x^7+5x^6+6x^4+30x^3+9x+45[/tex]

Answer :

To find the quotient of the given polynomials [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] and [tex]\((x^3 - 3)\)[/tex], we perform polynomial division, similar to long division but with polynomials. Here’s how you can understand the process:

1. Set up the division: The polynomial [tex]\(x^4 + 5x^3 - 3x - 15\)[/tex] is the dividend, and [tex]\(x^3 - 3\)[/tex] is the divisor.

2. Divide the leading term: Look at the leading term of the dividend, [tex]\(x^4\)[/tex], and the leading term of the divisor, [tex]\(x^3\)[/tex]. Divide these to find the first term of the quotient:
[tex]\[
\frac{x^4}{x^3} = x
\][/tex]

3. Multiply and subtract: Multiply the entire divisor [tex]\(x^3 - 3\)[/tex] by [tex]\(x\)[/tex]:
[tex]\[
x(x^3 - 3) = x^4 - 3x
\][/tex]
Subtract this from the original polynomial:
[tex]\[
(x^4 + 5x^3 - 3x - 15) - (x^4 - 3x) = 5x^3 + 0x^2 - 15
\][/tex]

4. Repeat the process: With the new polynomial [tex]\(5x^3 - 15\)[/tex], divide the leading term by the leading term of the divisor:
[tex]\[
\frac{5x^3}{x^3} = 5
\][/tex]
Multiply the entire divisor by this term:
[tex]\[
5(x^3 - 3) = 5x^3 - 15
\][/tex]
Subtract:
[tex]\[
(5x^3 - 15) - (5x^3 - 15) = 0
\][/tex]

5. No remainder: This subtraction leaves no remainder, confirming that the division process is complete.

The quotient of the division is therefore:
[tex]\[
x + 5
\][/tex]

This is the quotient when dividing [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] by [tex]\((x^3 - 3)\)[/tex], matching one of the given options.