Answer :
Answer:
The Correct Choice is Option (b).
Explanation:
We know that the product of two numbers is equal to the product of their highest common factor (HCF) and least common multiple (LCM).
Given:
HCF = 12
LCM = 336
One number = 84
Let the other number be [tex]\(y\).[/tex]
We have:
[tex]\[ \text{HCF} \times \text{LCM} = \text{Number 1} \times \text{Number 2} \][/tex]
Substituting the given values:
[tex]\[ 12 \times 336 = 84 \times y \][/tex]
[tex]\[ 4032 = 84y \][/tex]
Dividing both sides by 84:
[tex]\[ y = \frac{4032}{84} \][/tex]
[tex]\[ y = 48 \][/tex]
So, the other number is indeed [tex]\( \boxed{48} \).[/tex]